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A uniform bar has two small balls glued to its ends. The bar is 2.40m long and w

ID: 1288083 • Letter: A

Question

A uniform bar has two small balls glued to its ends. The bar is 2.40m long and with mass 3.80kg , while the balls each have mass 0.700kg and can be treated as point masses.

Part A: Find the moment of inertia of this combination about an axis perpendicular to the bar through its center.

Part B: Find the moment of inertia of this combination about an axis perpendicular to the bar through one of the balls.

Part C: Find the moment of inertia of this combination about an axis parallel to the bar through both balls.

Explanation / Answer

a) I = 3.80 x 2.42/12 + 2 x 0.7 x (1.2)2

= 3.84 kg*m^2

b) I = 3.80 x 2.42/3 + 0.7 x 2.42

= 11.328 kg*m^2

c) I = 0

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