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A net force F=5.00x newtons in the positive x direction acts on an object of mas

ID: 1284247 • Letter: A

Question

A net force F=5.00x newtons in the positive x direction acts on an object of mass 2.4kg for 5 meters.
A) what is the change in kinetic energy B) if the object were initially traveling at 30m/s in the negative direction what is its final speed C) what is the change in the momentum of the object A net force F=5.00x newtons in the positive x direction acts on an object of mass 2.4kg for 5 meters.
A) what is the change in kinetic energy B) if the object were initially traveling at 30m/s in the negative direction what is its final speed C) what is the change in the momentum of the object
A) what is the change in kinetic energy B) if the object were initially traveling at 30m/s in the negative direction what is its final speed C) what is the change in the momentum of the object

Explanation / Answer

( C ) change in momentum = mass * change in velocity

                                        = m*(v-u)

                                        = 2.4*(30.06 - (-30 ) ) = 2.4*60.06

                                        = 144.144 kgm/s

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