A 420?? resistor and a 6.10? ? F capacitor are connected in parallel to an ac ge

Question

A 420?? resistor and a 6.10??F capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220V at an angular frequency of 360rad/s . Note that since there is no inductor in the circuit, the 1/?L term is not present in the expression for Z.

Part A

Find the current amplitude in the resistor.

Part B

Find the current amplitude in the capacitor.

Part C

Find the phase angle of the source current with respect to the source voltage.

Part D

Find the amplitude of the current through the generator.

Part E

Does the source current lag or lead the source voltage?

Does the source current lag or lead the source voltage?

Please show All your work for points and ratings! Thank you!!!!

Explanation / Answer

Xc = 1/[(360)*( 10 x 10^-12)] = 277.8 M Ohms
ic = 220V/277.8MOhms = 0.79uA
iR = 220V/420 Ohm = 523,810 uA
Phase angle = arc tan ic/iR = arc tan (0.79/523810) = .00008 Degrees

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