How many molecules of HCl are formed when 80.0 g of water reacts according to th
ID: 1070201 • Letter: H
Question
How many molecules of HCl are formed when 80.0 g of water reacts according to the following balanced reaction? Assume excess ICl_3. ICl_3 + H_2O rightarrow ICl + HIO_3 + HCl 4.46 times 10^24 molecules HCl 2.68 times 10^24 molecules HCl 8.04 times 10^24 molecules HCl 5.36 times 10^24 molecules HCl 4.46 times 10^24 molecules HCl Determine the oxidation state of P in PO_3^3-. +3 +6 +2 0 -3 Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of MgSO_3 and HI are mixed. 2 H^+(aq) + SO_3^2-(aq) rightarrow H_2SO_3(s) Mg^2+(aq) + 2 I^-(aq) rightarrow MgI_2(s) 2 H^+(aq) + SO_3^2-(aq) + Mg^2+(aq) + 2 I^-(aq) rightarrow H_2SO_3(s) + MgI_2(aq) 2 H^+(aq) + SO_3^2-(aq) rightarrow H2O(l) + SO_2(g) No reaction occurs. What mass (in g) of AgCl is formed from the reaction of 75.0 mL of a 0.078 M AgC_2H_3O_2 solution with 55.0 mL of 0.109 M MgCl_2 solution? AgC_2H_3O_2(aq) + MgCl_2(aq) rightarrow AgCl(s) + Mg(C_2H_3O_2)_2(aq) 0.838 gExplanation / Answer
23) ICl3 + H2O ----- ICl + HIO3 + HCl
Number of moles of water = Mass/molar mass = 80/18 = 4.4444 moles
1 mole of H2O will form 1 mole of HCl
Moles of HCl formed = 4.4444 moles
Number of molecules of HCl formed = 4.4444 * 6.023 * 10^(23) molecules = 2.676 * 10^(24) molecules
Hence the correct answer is Option B
24)
Let the oxidation number of P be x
x + 3(-2) = -3
x = 3
Hence the oxidation number of Phosphorus will be equal to +3
correct answer is Option A
25) Reaction between MgSO3 + HI
MgSO3 + 2HI ------- MgI2 + H2O + SO2
Complete ionic equation
Mg2+(aq) + SO3 2-(aq) + 2H+(aq) + 2I-(aq) Mg2+(aq) + 2I-(aq) + SO2(g) + H2O(l)
correct answer is Option C
26)
Number of moles of AgC2H3O2 = 75/1000 * 0.078 = 0.00585 moles
Number of moles of MgCl2 = 55/1000 * 0.109 = 0.005995 moles
Hence AgC2H3O2 is the limiting reagent
Number of moles of AgCl formed = 0.00585 moles
Molar mass og AgCl = 108 + 35.5 = 143.5 gm/mol
Mass of AgCl formed = 0.00585 mol * 143.5 gm/mol = 0.839475 grams
Hence the correct answer is Option A
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