Which solution has the highest pH? (A) 0.10 M HBrO_3 (B) 0.10 M HBrO_4 (C) 0.10

Question

Which solution has the highest pH? (A) 0.10 M HBrO_3 (B) 0.10 M HBrO_4 (C) 0.10 M NaCN (D) 0.10M NaHCOO For the equilibrium shown below, what are the conjugate acid/base pairs? HF(aq) + H_2 O (aq) H_3 O^+ (aq) + F'(aq) (A) F^-/HF H_3 O^+/H_2 O (B) HF/F^- H_2 O/H_3 O^+ (C) HF/H_2 O F'/H_3 O^+ (D) H_3 O^+/F^- H_2 O/HF Which combination will not function as a buffer solution? (A) HCN/NaCN (B) HF/NaF (C) HNO_2/NaNO_2 (D) HNO_3/NaNO_3 What will happen when a small amount of barium hydroxide is added to a HCIO_2/NaCO_2 buffer? (A) (B) (C) (D) What is the K_1p of lead (III) chloride in terms of molar solubility, s? (A) s^2 (B) 2s^2 (C) 4s^2 (D) 4s^2

Explanation / Answer

1. HBrO3 being the weakest acid has highest ph. optuon A

2. Highest concentration of Hydroxide ions means most basic which is NAcN because HCN and HCOOH are acids and among Nacn and Nacooh , cn- having lower ka value makes Nacn more basic, option C

3. A conjugate acid is a species formed by the reception of a proton (H+) by a base—in other words, it is a basewith a hydrogen ion added to it. On the other hand, a conjugate base is merely what is left after an acid has donated a proton in a chemical reaction.

Among given options option 3 with F- as conjugate base and H30+ as conjugate acid satisfy definition. so option 3.

4.A buffer solution is an aqueous solution consisting of a mixture of a weak acidand its conjugate base, or vice versa. option 4 being the strong acid does not satisfy this criteria.

5.if strong alkali is added to the buffer the hydrogen ion concentration decreases by less than the amount expected for the quantity of alkali added.

The hydrogen ion concentration decreases by less than the amount expected because most of the added hydroxide ion is consumed in the reaction

OH + Hclo2 H2O + clo2

and only a little is consumed in the neutralization reaction which results in an increase in pH.

OH + H+ H2O

so option B

6.Pbcl2 (s) <=> Pb+2 (aq) + 2 cl- (aq) ..on dissociation 1s of Pb+2 and 2s of cl-
and the equilibrium condition is given by
Ksp = [Pb2+][cl-]^2

=s(2s)^2=4s^3 ..option D

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