A mixture of He, Ar, and Xe has a total pressure of 2 30 atm The partial pressur

Question

A mixture of He, Ar, and Xe has a total pressure of 2 30 atm The partial pressure of He is 0 2530 atm, and the partial pressure of Ar is 0200 atm What is the partial pressure of Xe? Express your answer to three significant figures and include the appropriate units Px_e = A volume of 18 0 L contains a mixture of 0 250 mole N_2, 0 250 mole O_2, and an unknown quantity of He The temperature of the mature is 0 degree C and the total pressure is 1 00 atm How many grams of helium are present n gas mixture Express your answer to three significant figures and include the appropriate units mass of He =

Explanation / Answer

A)
Ptotal = pHe + pAr + pXe
2.30 atm = 0.250 atm + 0.200 atm + pXe
pXe = 1.85 atm
Answer: 1.85 atm

B)
Let us 1st find the total number of gases present using,
P*V = n*R*T
1.00*18.0 = n*0.0821*(0+273)
n = 0.803 mol

total mol,
n = n (N2) + n(O2) + n(He)
0.803 = 0.250 + 0.250 + n(He)
n(He) = 0.303 mol

molar mass of helium = 4.00 g/mol
mass of He = number of mol * molar mass
= 0.303 mol * 4.00 g/mol
= 1.21 g
Answer: 1.21 g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.