Eg Masteringchemistry: Hwa32 Midterm 3 Topic Review-Google Chrome https:// 74516

Question

Eg Masteringchemistry: Hwa32 Midterm 3 Topic Review-Google Chrome https:// 74516401 Schafer Fall 2016 Chem 151 HWE32-Midterm 3 Topic Review Problem 6.72 Problem 6.72 Part A Assume that you have 1.50 mol of H2 and 3.50 mol ofN2. How many grams of ammonia (NH3) can you make, and how many grams of which reactant will be left over? 3H2 +N2 2NH3 mNH1 Submit My Answers Give U Part B My Answers Give Up Submit Part C 2.9 Submit Answers Incorrect, Try Again; 4 attempts remaining a Signed in as Miriam Adam Help Close Resources previous l 7 of 12 l next. BravideEestask Continue a 0:07 PM /24/2016

Explanation / Answer

The balanced chemical equation for the reaction is:

N2 + 3H2 -----------------------> 2NH3

From the balanced chemical equation we get the information that:

1 mole of N2 reacts with 3 moles of H2 and forms ------------ 2 moles of ammonia

that is

1 mole of N2 reacts with 3 moles of H2 and forms ------------ 2x17g = 34 g of ammonia

It isgiven that :

1.50moles of H2 and 3.50moles of N2 are reacting.

But we know 1 mole of N2 reacts with 3 moles of H2

then 3.5moles of N2 requires ---------?moles of H2

= 3.5x3 /1 = 10.5 moles of H2

but we have only 1.5moles of H2. Hence H2 amount is less than required ,hence it is the limiting reagent.

N2 is the excess reagent.

3 moles of H2 reacts with 1 mole of N2

1.5 moles of H2 reacts with ------------ ? moles of N2

= 1.5 x1 /3 = 0.5 moles of N2

Amonut of excess reagent remaining that is N2 remaining after the reaction= 3.5-0.5 = 3 moles

Amount of Ammonia formed in the reaction is:

From the balanced equation :

3 moles of H2 is forming ---------- 34g of ammonia

then 1.5moles of H2 forms --------? g of ammonia

= 34g x 1.5 moles / 3moles

= 17g of ammonia

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.