Part A Acid spills are often neutralized with sodium carbonate or sodium hydroge

Question

Part A

Acid spills are often neutralized with sodium carbonate or sodium hydrogen carbonate. For the neutralization of acetic acid, the unbalanced equations are
(1) CH3CO2H(l)+Na2CO3(s)CH3CO2Na(aq)+CO2(g)+H2O(l)
(2) CH3CO2H(l)+NaHCO3(s)CH3CO2Na(aq)+CO2(g)+H2O(l)
Balance both equations.

Express your answers as chemical equations separated by a comma. Identify all of the phases in your answer.

2CH3CO2H(l)+Na2CO3(s)2CH3CO2Na(aq)+CO2(g)+H2O(l),CH3CO2H(l)+NaHCO3(s)CH3CO2Na(aq)+CO2(g)+H2O(l)

Correct

Part B

How many kilograms of each substance is needed to neutralize a 3.800 gallon spill of pure acetic acid (density = 1.049 g/ml)?

Enter your answers using four significant figures separated by a comma. NOTE: (503, 251.5) and (3.521, 5.581) are incorrect attempts i have made

Part C

How much heat in kilojoules is absorbed or liberated in each reaction? See Appendix B for standard heats of formation; Hf = -726.1 kJ/mol for CH3CO2Na(aq).

Enter your answers using three significant figures separated by a comma.

2CH3CO2H(l)+Na2CO3(s)2CH3CO2Na(aq)+CO2(g)+H2O(l),CH3CO2H(l)+NaHCO3(s)CH3CO2Na(aq)+CO2(g)+H2O(l)

Explanation / Answer

Part B:

1 gallon = 3.78 L

Then, 3.8 gallons = 3.8*3.78 = 14.36 L

1 mL of acetic acid = 1.049 g. of acetic acid

then, 14360 mL of acetic acid = 14360*1.049 = 15064 g. of acetic acid = 15.06 kg of acetic acid.

According to balanced equation with sodium carbonate,

120 g. of acetic acdi = 106 g. of sodium carbonate

0.120 kg of acetic acid = 0.106 kg. of sodium carbonate

then, 15.06 kg of acetic acid = 15.06*0.106 = 1.596kg of soidum carbonate is needed.

Similarly according to the balanced equation with sodium bicarbonate,

60 g. of acetic acid = 84 g. of sodium bi carbonate

0.060 kg. acetic acid = 0.084 kg. of sodium bicarbonate

Then, 15.06 kg of acetic acid = 15.06*0.084 = 1.265 kg of sodium bicarbonate is needed.

Part C:

According to the given balanced equations,

in a first instance (with Na2CO3)

-726.1*2 = - 1452.2 kJ of heat is released.

In a second instance (with NaHCO3)

- 726.1 kJ of heat is released.

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