Part A A sample of gas in a balloon has an initial temperature of 43 C and a vol

Question

Part A

A sample of gas in a balloon has an initial temperature of 43 C and a volume of 1.48×103 L . If the temperature changes to 82 C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

Express your answer with the appropriate units.

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Part B

What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 43 C, V1= 1.48×103 L ) to a volume of 2.96×103 L ? Assume no change in pressure or the amount of gas in the balloon.

Express your answer with the appropriate units.

Explanation / Answer

Part A

Initial temperature T1= 43 deg celsius= 43+ 273 = 316 K

Initial volume= 1.48 x 103 L

New temperature= 82 deg celsius= 82 + 273 = 355 K

Given no change in pressure and amount of gas, (means P1=P2(pressure of gas) and n1=n2(moles of gas)),

Using ideal gas equation PV = nRT,

P1V1/T1= P2V2/T2 (where P1 and P2 cancel) =>

so => V2= V1 * T2 / T1 => 1.48 x 103 x 355 / 316 => 1.66 x 103 L

Part B

In thsi case, V2= 2.96 x 103 L, Rest everything is same,

then using P1V1/T1=P2V2/T2,

we have T2 = V2 x T1 / V1 => 2.96 x 103 / 1.48 x 10 3 x 316 K

=> 632 K => 632 - 273 => 359 deg celsius

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