Look at the four sets of quantum numbers below. How many sets are not allowed? n

Question

Look at the four sets of quantum numbers below. How many sets are not allowed? n = 1, I = 0, m_l = 0, m_s = 1/2 n = 2, I = 2, m_l = 2, m_s = -1/2 n = 3, I = 2, m_l = -2, m_s = -1/2 n = 4, I = 3, m_l = -3, m_s = 1/2 all four sets are allowed one set is not allowed two sets are not allowed three sets are not allowed all four sets are not allowed Consider a 1L container of argon and a 1L container of helium. The gas In each container is at STP. Which statement below Is correct? The density in grams/mL of each gas Is the same. The mass of the gas is the same in the two containers The speed of the atoms is the same in the two containers. The number of atoms Is the same in the two containers. What is the molar mass of a gas that diffuses through a small hole at twice the rate of gaseous iodine (I_2, 252 g/mol) if the gases are at the same temperature? 514 g/mol 180 g/mol 126 g/mol 63 g/mol Nitrosylazide has the formula ON_4 and atom connectivity: 0-N-N-N-N. Which of t e four structures below is the best structure? Which of the following, when mixed as 0.1 M aqueous solutions, will result in the formation of a precipitate? K_2 SO_4 and CrCl_3 KOH and Ba(NO_3)_2 NiBr_2 and AgNO_3 Li_2CO_3 and Csl

Explanation / Answer

23)

we know tha t

the value of l ranges from 0 to n-1

and

the value of m ranges from -l to + l

now

from the given list

the second set is not allowed because , l value should be less than 2

the remaining sets are allowed

so

the answer is b) one set is not allowed

24)

we know that

for gases

PV = nRT

n = P x V / RT

given at STP volumes are same

so

moles of argon = moles of Helium

we know that

equal moles of gases contain equal number of atoms

so

the answer is

d) the number of atoms is the same in the two containers

25)

we know that

r2/r1 = sqrt ( M1/M2)

so

2 = sqrt ( 252 / M2)

4 = 252 / M2

M2 = 63

so

the molar mass of the second gas should be 63 g/mol

so

the answer is d) 63 g/mol

26)

the answer is option B)

27)

NiBr2 + 2AgN03 --> Ni(N03)2 + AgBr (s)

AgBr is insoluble in water , so it precipitates out

so

the answer is option c

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