Look at the diagram of a prokaryotic promoter and answer the following questions

Question

Look at the diagram of a prokaryotic promoter and answer the following questions 1-4 Prokaryotic pronoter 5' dSDNA 3" 30 20 10 What is the function of the sequence of DNA marked by label b? (1pt) 2. Which letter marks where transcription will start? (1pt) 3. Will the top or bottom strand be transcribed into RNA? (1pt) 4. Which DNA nucleotide (A, T, C or G) should be in location marked by the lettere? (1pt) 5. RNA polymerase is a holoenzyme. What must bind to RNA polymerase for it to become an activated, 'whole" enzyme? (1pt) 6. Which of the following will mark the end of transcription? Put an X next to the option you want to select or change the font color. (1pt) a. nucleated sequence b. release sequence c. relief sequence d. stop sequence e. terminator sequence

Explanation / Answer

1. 'b' represents the complementary consensus sequence (at - 35 position) 5'-TTGACA-3' which helps recognise the location for binding of RNA polymerase to start the RNA Synthesis 35 bp downstream to the consensus sequence.

2. 'e' marks the transcription start site.

3. RNA polymerase will use bottom (3' to 5') stand as template to synthesize RNA strand identical to the top (5' to 3') strand. So top strand will be the identical RNA bring formed after transcription.

4. 'T' since start codon is ATG. So 5' to 3' (top) strand of double stranded DNA will have 'A' at position marked 1, the complementary to it at position marked 'e' will be 'T'.

5. Sigma factor binds and activates holoenzyme. It helps in recognition of consensus sequences at -35 and -10 bp location to the transcription start site.

6. e (terminator sequence).

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