Look at the diagram of the two-loop circuit in procedure 1. a) What are the dire

Question

Look at the diagram of the two-loop circuit in procedure 1. a) What are the directions of Ix (the current through battery Vx) and (the current through battery Vy)? Ix is toward A, Iy is toward C Ix is toward F, Iy, is toward C Ix is toward F, Iy, is toward D Ix is toward A, Iy, is toward D Both depend on the values of the voltages and resistors c) To measure the difference in potential across battery Vx, we can place the voltmeter in parallel with Vx in the circuit between point B and R2 in the circuit between B and C in parallel with R1 in the circuit between A and B NOTE: Watch out for signs d) In a complex circuit: point M is a junction of six current-carrying wires, numbered 1 to 6. We will adopt the convention that a current has a positive value if it flows into the junction, and has a negative value if it flows away from the junction. Now, suppose we measure the following values: i. Find the current I6. ii. Now suppose that the current in wire 1 flows from point M to point N, and the resistance of wire MN is 61.2 ohm. If point M is at potential VM = 972 V, the potential at point N is delta VN =

Explanation / Answer

a) The direction of Ix and Iy depends upon the value of resistors and voltages across batteries connected in the circuit.

c) A voltmeter is an instrument used for measuring electrical potential difference between two points in an electric circuit. It is connected in parallel with the component whose potential is to be measured.

So voltmeter will be connected in parallel with Vx to measure its potential difference.

d)According to Kirchhoff's current law (KCL)

At any node (junction) in an electrical circuit, the sum of currents flowing into that node is equal to the sum of currents flowing out of that node

or equivalently

The algebraic sum of currents in a network of conductors meeting at a point is zero.

I1+I2+I3+I4+I5+I6 = 0

+41.9-76.7-49.1+43.8+52.7+I6 = 0

I6 = 12.6 A <---------

Now the current in wire 1 is 41.9A as given in question (I1=41.9A)

Current flows from M to N then M is at higher potential compared with the N.

Potential of M= Vm=972V Resistance of MN = 61.2ohm

Potential of N = Vn

Vm - Vn = I1*R

972- Vn = 41.9*61.2

Vn = 972-2564.20= -1592.28V

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