A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C.

Question

A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C. The initial concentrations of Pb2+ and Cu2+ are 5.30×102 M and 1.60 M , respectively.

Part A:

What is the initial cell potential? Ecell= 0.51V

Part B

What is the cell potential when the concentration of Cu2+ has fallen to 0.220 M ?

Part C

What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.350 V ?

Enter your answers numerically separated by a comma. Express your answer using two significant figures.

Explanation / Answer

Pb (s) + Cu2+ = Pb2+ + Cu(S)

NEERST EQUATION

                ECELL = E0- .059 / n log [Pb2+] /[ Cu2+]     n= 2 electron

part A

.47 V

B .491 V

C.

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