A reaction has a standard free-energy change of –3.82 kJ/mol at 25 °C. What are

Question

A reaction has a standard free-energy change of –3.82 kJ/mol at 25 °C.

What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively?

[A]=___M [B]=___M [C]=_____M

How would your answers above change if the reaction had a standard free-energy change of 3.82 kJ/mol?

A) All concentrations would be lower.

B) There would be no change to the answers.

C) There would be less A and B but more C.

D) There would be more A and B but less C.

E) All concentrations would be higher.

Explanation / Answer

A:- C) There would be less A and B but more C. => Because A + B <------> C , Because the equilibrium is exists between reactants and product, hence at initial time the concentration of reactants more and product concentration is zero. At equilibrium the concentration of reactants (A, B) arre low (less) and the cocentration of product (C) is more.

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