A reaction A (aq)+ b(aq) C(aq) has a standard free-energy change of -4.69 kJ/mol

Question

A reaction A (aq)+ b(aq) C(aq) has a standard free-energy change of -4.69 kJ/mol at 25 degree C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? How would your answers above change if the reaction had a standard free-energy change of +4.69 kJ/mol? All concentrations would be higher, There would be more A and B but less C. There would be no change to the answers There would be less A and B but more C. All concentrations would be lower.

Explanation / Answer

limiting reagent is A thus conc of A=0 conc of B=40-30=10 conc of C=0+30=30 negative change in free energy favourable thus there would be more A and B but less C

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