A. A sample of neon gas at a pressure of 0.585 atm and a temperature of 22.6 ° C

Question

A. A sample of neon gas at a pressure of 0.585 atm and a temperature of 22.6 °C, occupies a volume of 14.9 liters. If the gas is allowed to expand at constant temperature to a volume of 25.9 liters, the pressure of the gas sample will be?

B. A sample of xenon gas at a pressure of 1.15 atm and a temperature of 26.3 °C, occupies a volume of 17.6 liters. If the gas is compressed at constant temperature to a volume of 10.1 liters, the pressure of the gas sample will be

C. A sample of methane gas at a pressure of 0.960 atm and a temperature of 25.2 °C, occupies a volume of 877 mL. If the gas is allowed to expand at constant temperature until its pressure is 0.628 atm, the volume of the gas sample will be

Explanation / Answer

A. Using,

P1V1 = P2V2

with,

P1 = 0.585 atm

V1 = 14.9 L

V2 = 25.9 L

we get new pressure P2 of neon,

P2V2 = P1V1

P2 = 0.585 atm x 14.9 L/25.9 L = 0.336 atm

B. Using,

P1V1 = P2V2

with,

P1 = 1.15 atm

V1 = 17.6 L

V2 = 10.1 L

we get new pressure P2 of xenon,

P2V2 = P1V1

P2 = 1.15 atm x 17.6 L/10.1 L = 2.00 atm

C. Using,

P1V1 = P2V2

with,

P1 = 0.960 atm

V1 = 0.877 L

P2 = 0.628 atm

we get new volume V2 of methane,

P2V2 = P1V1

V2 = 0.960 atm x 0.877 L/0.628 atm = 1.34 L

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