A 65.56 g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evap

Question

A 65.56 g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evaporate) in a position like apparatus. Calculate the expansion work done against external pressure of 0.956 atm and at a constant temperature of 22C. Assume that the initial volume of dry ice id negligible and the CO2 behaves as an ideal gas (1L•atm=101.3J) A 65.56 g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evaporate) in a position like apparatus. Calculate the expansion work done against external pressure of 0.956 atm and at a constant temperature of 22C. Assume that the initial volume of dry ice id negligible and the CO2 behaves as an ideal gas (1L•atm=101.3J)

Explanation / Answer

work done = - Pexternal x difference in volume.

Here, initial volume is zero. and the final volum can be determined by using idealgas equation PV=nRT;

P=Pexternal= 0.956 atm, Temperature= 22+273= 295 K , V= nRT/P

65.56 g of solid CO2 gets converted to gas. so number of mole of gaseous CO2= 65.56/44 = 1.49

so V= nRT/P= (1.49 x 0.0821x 295)/0.956 = 37.748 L

so work done= -(0.956)x(37.748)= 36.087 L•atm

but 1L•atm=101.3J so expansion work done in joule= -36.087 x 101.3J= 3655.619 Joule=- 3.655 KJ

Neagative sign indicates the work done by the system.

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