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The problems below focus on Sex-Linked traits. I would suggest you complete the

ID: 99515 • Letter: T

Question

The problems below focus on Sex-Linked traits. I would suggest you complete the problems on this page, and then submit your answer in the Assignment #1D .. Assume that a man is color-blind. Color-blindness is caused by an X-linked recessive disease. Alleles: XC = normal Xc = colorblind Y = carries no version of the allele a. What is the man's genotype. Use correct nomenclature: b. Assume this man marries a woman that is homozygous normal at the color-blind gene. What is her genotype? c. What is the probability if this couple has children that the child will be a son that is colorblind? Show your Punnett square. d. Using the Punnett square above, what is the probability that his daughters will be colorblind? e. Using the Punnett square above, what is the probability that his daughters will be carriers of the disease? Red-green color blindness is an X-linked recessive disease. A woman is red-green color-blind. (Use the same alleles as above) a. What was this woman's fathers genotype? b. If this woman has children with a normal male, what fraction of her children will be color blind? c. What fraction of her sons will be color blind?

Explanation / Answer

1a. The man's genotype is XcY.

Males have one X and one Y chromosome. As color blindness is X-linked recessive disease, the genotype is XcY.

Xc stands for colorblind allele and Y carries no version of the allele.

1b. The genotype of homozygous normal woman is XCXC.

1c. Colorblind man (XcY) marries with homozygous normal woman (XCXC)

Punnet square showing probability of son of this couple.

Thus, the probability of this couple's son that will be colorblind is 0%.

1d. The probablity of daughters that will be colorblind is 0%.

1e. The probability of daughters that will be carrier is 100%.

2a. The father's genotype of red green colorblind woman was XcY.

2b. If this woman (XcXc) marries with normal male (XCY):

Thus, 50% of her children will be colorblind and

50% of her children will be carriers of colorblindness.

2c. The colorblind woman will have 100% of her sons colorblind.

XC XC Xc XcXC XcXC Y XCY XCY