25.0 mL of a 1.00 M Fe(NO3)2 solution was reactant with 25.0 mL of a 0.700 M sol

Question

25.0 mL of a 1.00 M Fe(NO3)2 solution was reactant with 25.0 mL of a 0.700 M solution of K3PO4 to produce the solid Fe3(PO4)2
3 Fe(NO3)2(aq) + 2 K3PO4aq) ---> Fe3(PO4)2(s) + 6 KNO3(aq)
What is the limiting reagent?
How many grams of Fe3(PO4)2 will be produced? 25.0 mL of a 1.00 M Fe(NO3)2 solution was reactant with 25.0 mL of a 0.700 M solution of K3PO4 to produce the solid Fe3(PO4)2
3 Fe(NO3)2(aq) + 2 K3PO4aq) ---> Fe3(PO4)2(s) + 6 KNO3(aq)
What is the limiting reagent?
How many grams of Fe3(PO4)2 will be produced?
3 Fe(NO3)2(aq) + 2 K3PO4aq) ---> Fe3(PO4)2(s) + 6 KNO3(aq)
What is the limiting reagent?
How many grams of Fe3(PO4)2 will be produced?

Explanation / Answer

Limiting reagent is Fe(NO3)2

2.978g will be produced

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