A reaction has an enthalpy, Delta H*_rxn equal to 121.5 kj and a Delta H*_rxn eq

Question

A reaction has an enthalpy, Delta H*_rxn equal to 121.5 kj and a Delta H*_rxn equal to 325 J/K. Is the reaction spontaneous or nonspontancous at 15 degree C? spontaneous at 25degreeC nonspontancous at 25degreeC can not be determined Is 25degreeC a high temperature or a low temperature for the reaction in problem #4? a low temperature since the reaction is spontaneous a high temperature since the reaction is nonspontaneous a low temperature since the reaction is nonspontancous a high temperature since the reaction is spontaneous At what temperature, degreeC, will the reaction in problem #4 changc its spontaneity? 100.7 degreeC 80.0 degreeC 30.7 degreeC 0.0 degreeC it is non spontaneous at all temperatures

Explanation / Answer

delta G = delta H - T*delta S

Now, delta G = 121500 - 298*325 = 24650 J

Since delta G > 0 , the reaction is non-spontaneous

Now, the reaction to be spontaneous, delta G <0

Thus, delta H - T*delta S < 0

or, 121500 - T*325 < 0

or, T > 373.8 K

or, T > 100.8 0C

Thus, the spontaneity will change at temperature 100.8 0C

So the correct option is (A)

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