The reaction NO_2CI NO_2 + 1/2CI_2 is first order and appears to follow the mech

Question

The reaction NO_2CI NO_2 + 1/2CI_2 is first order and appears to follow the mechanism NO_2Cl NO_2 + Cl NO_2Cl + Cl NO_2 + Cl_2 Assuming a steady state for the chlorine atom concentration, show that the empirical first-order rate constant can be identified with 2k_1. The following data were obtained at 180 degree C. In a single experiment the reaction is first order, and the empirical rate constant is represented by k. Show that the reaction is second order at these low gas pressures and calculate the second-order rate constant.

Explanation / Answer

A) In order to show the empirical first order rate is 2k1, we need to sum the two partial reactions.

NO2Cl------>NO2 +Cl

NO2Cl+Cl----->NO2+Cl2

_______________________

2NO2Cl----->2NO+ Cl2

So, the resulting reaction is pretty similar to the one with rate k1 if we take out two as common factor

2*(NO2Cl---->NO2+1/2Cl2) is exactly the same reaction as the partial reaction with k1 just multiplied by a 2 factor so the reaction rate for this reaction is equal to 2k1.

B) K= 3.4 x 103 cm3 mol-1 s -1.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.