The reaction A + B -- > C has a delta G\'° of –20 kJ/mol at 25° C. Starting unde

Question

The reaction A + B -- > C has a delta G'° of –20 kJ/mol at 25° C. Starting under standard conditions, one can predict that:
A. at equilibrium, the concentration of B will exceed the concentration of A.    
B. at equilibrium, the concentration of C will be less than the concentration of A.    
C. at equilibrium, the concentration of C will be much greater than the concentration of A or B.    
D. C will rapidly break down to A + B.    
E. when A and B are mixed, the reaction will proceed rapidly toward formation of C.

Explanation / Answer

DeltaG = -RTlnK

R = gas constant = 0.008314 KJ / mol K

K = equilibrium constant

T = Temperature = 298 K

DeltaG = -20 KJ / mole

Putting values

-20 = - 0.008314 X 298 X lnK

lnK = 8.072

K = 3203.502

K > 1 so the reaction will go in forward direction

So at equilibrium the concentration of C will be much greater than the concentration of A or B

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