The quantity of antimony in an ore can be determined by an oxidation-reduction t

Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb^3+(aq). The Sb^3+(aq) is completely oxidized by an aqueous solution of BrO_3^-(aq). Complete and balance the equation for this reaction in acidic solution. BrO_3^- + Sb^3+ rightarrow Br^- + Sb^5+ Tip: If you need to clear your work and reset the equation, click the button that looks like two red arrows.

Explanation / Answer

BrO3- + Sb3+ ---> Br- + Sb5+

Br goes from +5 to -1 oxidation state by gaining 6 e-

Sb3+ goes to +3 to +5 by loosing 2 e-

balance electrons,

BrO3- + 3Sb3+ ---> Br- + 3Sb5+

Balance O,

BrO3- + 3Sb3+ ---> Br- + 3Sb5+ + 3H2O

Balance H,

BrO3- + 3Sb3+ + 6H+ ---> Br- + 3Sb5+ + 3H2O

This is the final balanced equation

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