Enthalpy (Heat) of Neutralization for an Acid-Base Reaction 1. Volume of acid (m

Question

Enthalpy (Heat) of Neutralization for an Acid-Base Reaction 1. Volume of acid (mL) 2. Temperature of acid (degreeC) 3. Volume of NaOH (mL) 4. Temperature of NaOH 9degreeC) 5. Exact molar concentration of NaOH (mol/L) 6. Maximum temperature from graph (degreeC) 7. Instructor's approval of graph Calculations for Enthalpy (Heat) of Neutralization for an Acid-Base Reaction 1. Average initial temperature of acid and NaOH (degreeC) 2. Temperature change. DeltaT(degreeC) 3. Volume of final mixture (mL) 4. Mass of final mixture (g) (Assume Ihe density of the solution is 1.0 g/mL.) 5. Specific heat of mixture 6. Heat evolved (J) 7. Moles of OH^- reacted, the limiting reactant (mol) 8. Moles of H20 formed (moL) 9. DeltaH (kJ/mol H_20), equation 25.8 10. Average DeltaH_B (kJ/mol H_20) Show calculations for Trial I using the correct number of significant figures.

Explanation / Answer

1. Average initial temperature of acid and NaOH = 22 oC

2. Temperature change = 6.5 oC

3. Volume of final mixture = 100 ml

4. Mass of final micture = 100 g

5. Specific heat of mixture = 4.18 J/g.oC

6. Heat evolved = 100 x 4.18 x 6.5 = 2717 J

7. Moles of OH- reacted = 0.9830 M x 50 ml = 0.04915 mol

8. moles of H2O formed = 0.04915 mol

9. dHn (kJ/mol H2O) = -2717/0.04915 = -55.28 kJ/mol

10. Average dHn = -55.28 kJ/mol

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