Enthalpy (Heat) of Neutralization for an Acid-Base Reaction Volume of acid (mL)
ID: 1059173 • Letter: E
Question
Enthalpy (Heat) of Neutralization for an Acid-Base Reaction Volume of acid (mL) Temperature of acid (degree C) Volume of NaOH (mL) Temperature of NaOH (degree C) Exact molar concentration of NaOH (degree C) Exact molar concentration of NaOH (mol/L) Maximum temperature from graph (degree C) Instructor's approval of graph Calculations for Enthalpy (Heat) and Neutralization for an Acid-Base Reaction Average initial temperature of acid and NaOH (degree C) Temperature change, Delta T (degree C) Volume of final mixture (mL) Mass of final mixture (g) (Assume the density of the solution is 1.0 g/mL.) Specific heat of mixture Heat evolved (J) Moles of OH^- reacted, the limiting reactant (mol) Delta H_a (kJ/mol H_2 O), equation 25.8 Average Delta H_a (kJ/mol H_2 O) Show calculations for Trial 1 using the correct number of significant figures.Explanation / Answer
1. Avg intial temperature HCl + NaOH = 22.55 oC
Temperature change T = 27.8 - 22.55 = 5.25o C
Volume of the final mixture = Volume of HCl + volume of NaOH = 30 + 30 = 60mL
mass of the final mixture = 60 mL * 1gm/mL = 60 gm
Heat evolved = mCpT = 60 gm * 4.18 J /gmo C * 5.25 oC = 1316.7 J
moles of OH- reacted = Exact molar concentration of NaOH * 60mL
mol/lit * 0.06 lit = moles of OH- reacted
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