Enter your answer into the provided box. The energy needed for the following pro

Question

Enter your answer into the provided box. The energy needed for the following process is 1.960 × 104 kJ/mol: Li(g) Li (g)+ 3c If the first ionization energy of lithium is 5.20 x 10' k.J/mol, calculate the second ionization energy of lithium-that is, the energy required for the process: Li'(g) ? Li2(g) + e A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen- like ion are given by where En is the energy of the electron in the hydrogen-like ion, n is the principal quantum number, and Z is the atomic number of the element En =-(2.18 × 10 18 J) (2t)(1/?) Second ionization energy of lithium: k.J/mol (Enter your answer in scientific notation) References

Explanation / Answer

energy of Li2+ = (2.18*10^-18)*(2^2/1^2)

Third ionisation eenrgy per atom = 8.72*10^-18 j

Third ionisation eenrgy per mol = 8.72*10^-18*6.023*10^23

                                  = 5.25*10^3 kj/mol

second ionisation eenrgy = (1.960*10^4) - (5.25*10^3)

                         = 1.435*10^4 kj/mol

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