electrochemistry lab report 1. which cell produces the highest cell potential? e

Question

electrochemistry lab report

1. which cell produces the highest cell potential? explain

2. which cell produces the lowest cell potential? explain.

3. Did the reduced concentration of Cu2+ ion using the .5M Cu(NO3)2 and .1M Cu(NO3)2 solutions affect the cell potentials? explain

4. what is the oxidizing agent in the Zn-Mg cell?

5.Compare the sum of Cu-Zn and the Zn-Mg cell potentials with the Cu-Mg cell potential. what can you conclude?

6. What effect, if any, would varying the concentraion of both the aqueous species have on cell potentials? what about the varying size of electrodes?

Explanation / Answer

I will answer the first 3 questions:

Let's calculate the potential of every cell basing on your calculations data:
For a better understanding, I will label E1, E2, E3 and so on, in the same order the potentials are in the chart, we have 5 cells, so:

E1 = 0.901 - 0.059/2 log1 = 0.901 V
E2 = 0.60 - 0.059/2 log(1/0.5) = 0.5911 V
E3 = 0.871 - 0.059/2 log(1/0.1) = 0.842 V
E4 = 0.6 - 0.059/2 log1 = 0.6 V
E5 = 1.296 - 0.059/2 log1 = 1.296 V

Therefore, The Cell Cu-Mg produces the largest cell potential, and the cell Zn-Cu with concentrations of 1 and 0.5 M is the lowest cell potential.

We can see in that cell, that when Cu is reducted, the value of Q gets bigger, this means that the logarism will be a smaller value and therefore, the cell potential will be lowered (See E2 and E3)

Hope this helps

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.