A. Empirical Formula of a magnesium oxide Mass of crucible and cover + magnesium

Question

A. Empirical Formula of a magnesium oxide

Mass of crucible and cover + magnesium metal (before heating)       = 43.59 grams

Mass of crucible and cover                                                                  = 42.80 grams

Mass of magnesium  metal                                                                   = 0.079 grams

mass of crucible and cover + magnesium oxide(after heating)             = 38.38 grams

mass of combined oxygen (after heating - before heating)                   = 0.0521 grams

Show the calculation for the empirical formula.

Explanation / Answer

no of mol of Mg = 0.079/24 = 0.0033 mol

No of mol of O = 0.0521/16 = 0.00326 mol

simplest ratio

Mg = 0.0033/0.00326 = 1.01

O = 0.00326/0.00326 = 1

empirical formula = MgO

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