A. Determine the Reaction Order for HCl using calculations described in the Back

Question

A. Determine the Reaction Order for HCl using calculations described in the Background section. Show your work. Note that your answer will probably not be an even whole number as it is in the examples, so round to the nearest whole number.

B. Determine the Reaction Order for Na2S2O3using calculations described in the background section. Show your work. Note that your answer will probably not be an even whole number as it is in the examples. Write the rate law for the reaction between HCl and Na2S2O3.?

Experiment 1 Experiment 2 Experiment 3 Initial Concentration NO1 0.010 M 0.020 M 0.010 M Initial Concentration [O 0.020 M 0.020 M 0.040 M Initial Rate 0.025 M/s 0.105 M/s 0.050 M/s

Explanation / Answer

you have given the data of [NO] and [O2]

so i am calculating according to it if you want HCl and Na2S2O3 orders

substituteHCl and Na2S2O3 in those places so that you will get the ans.

rate= k[NO]^x [O2]^y

by observing exp1 and exp.2

0.025 = k[0.01]^x[0.02]^y ...............1

0.105 = k[0.02]^x[0.02]^y ...............2

do 1/2

0.025/0.105 = (0.01/0.02)^x

0.24 = (0.5)^x

(0.5)^2 = (0.5)^x

bases are equal powers should be equated

x = 2

so the order with respect to [NO] is 2

by observing exp1 and exp3

0.05= k[0.01]^x[0.04]^y .................3

do eq.1/eq.3

(0.025/0.5) = (0.02/0.04)^y

(0.5)^1 = (0.5)^y

so y =1

the order w,r.t. to [O2] is 1

total order of the reaction is =(2+1) = 3

rate law

rate = K[NO2]^2[O2]

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