The reactions for the ionization energy of potassium and the electron affinity o

Question

The reactions for the ionization energy of potassium and the electron affinity of bromine can be combined to give the reaction shown in the introduction: K(g) rightarrow K^+(g) + e^- Br(g) + e^- rightarrow Br^-(g) K(g) + Br(g) rightarrow K^+(g) + Br^-(g) The ionization energy for potassium is 419 kJ/mol. The electron affinity for bromine is -325 kJ/mol. Use these values and Hess's law to calculate lhe change in enthalpy for the following reaction per mole of reagent: K(g) + Br(g) rightarrow K^+(g) + Br^-(g), delta H = ? Express your answer with the appropriate units.

Explanation / Answer

DHrxn = (419-325) = 94 kj/mol

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.