The reaction of the diazonium salt with N,N-dimethylaniline leads to methyl oran

Question

The reaction of the diazonium salt with N,N-dimethylaniline leads to methyl orange. Which of the following statements are correct? Question options:

The diazonium salt formed in the first step is present as a white precipitate in the reaction mixture.

Glacial acetic acid is dilute acetic acid in water.

N,N-dimethylaniline is dissolved in glacial acetic acid before addition.

The reaction should be heated to reflux for the electrophilic aromatic substitution to proceed.

the reaction mixture is acidic all throughout the synthesis.

Sodium hydroxide has to be added slowly because the reaction of acid with NaOH is exothermic.

The synthesized dye methyl orange is dissolved in alkaline conditions so that we can obtain purified methyl orange by recrystallization.

Explanation / Answer

1)true-A white ppt of diazonium salt is formed

2) False -glacial acetic acid is ice-like crystals of acetic acid that is formed below room temperature at 16.6C

3)true-. N,N-dimethylaniline is dissolved in glacial acetic acid before addition, as the reaction happens at low temperatures.

4)False -coupling of diazonium and N,N-dimethylaniline happens at low temperatures 0-5C

5)False- NaOH is added to get the sodium salt of methyl orange product.

6)False-Actual coupling occurs when NaOH is added.If it is added quickly., dimethyl aniline may separate as oily phase and leave an equal amount of diazonium salt unreacted,( which may eventually may decompose into brown tar and contaminate the product)

7)False -it is recrystallised from alcohol

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