The experiment calls for preparing one of two salts, either copper(ii) sulfate o

Question

The experiment calls for preparing one of two salts, either copper(ii) sulfate or potassium aluminum sulfate. The instructions for the copper(ii) sulfate preparation give a target of between 0.010 and 0.025 moles of the copper(ii) sulfate product. The instructions also specify to use an excess of sulfuric acid but not more than 5 times the amount required by the balanced equation. Sulfuric acid will be available as a 6.0 M H2SO4 solution. What is the volume of 6.0 M H2SO4 required by the balanced equation to react with the CuO to produce 0.025 moles of copper(ii) sulfate. Report the volume needed BEFORE allowing for excess in milliliters to two significant figures. Don not include units in the answer box.

Explanation / Answer

H2SO4 + CuO ------> CuSO4 + H2O

1mol of CuO produces 1 mol of CuSO4, so 0.025 mol of CuSO4 were produced by 0.025 mol of CuO and 0.025 mol of H2SO4.

Volume of H2SO4= 0.025 mol/6.0M = 4.2x10-3L = 4.2 mL

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