A) Find the pH of a 0.284 M NaF solution. (The K a of hydrofluoric acid, HF, is

Question

A) Find the pH of a 0.284 M NaF solution. (The Ka of hydrofluoric acid, HF, is 3.5×104.)

B) Determine the [OH] of a 0.26 M solution of NaHCO3. Express your answer using two significant figures.

- Determine the pH of this solution. Express your answer to two decimal places.

C) For each strong base solution, determine [H3O+],[OH], pH, and pOH.:

Express your answer using both three significant figures and then to three decimal places

8.84×103 M LiOH

1.12×102 M Ba(OH)2 .

Express your answer using both two significant figures and two decimal places

2.2×104 M KOH

4.8×104 M Ca(OH)2

Explanation / Answer

A)

pH =

NAF = NA+ and F-

F- + H2O <-> HF + OH-

Kb =[ HF ][OH-]/[F-]

Kb = Kw/Ka = (10^-14)/(3.5*10^-4) =2.8571*10^-11

Kb =[ HF ][OH-]/[F-]

2.8571*10^-11 =x*x/(0.284-x)

x = [OH-] = 2.84*10^-6

pOH = -log(2.84*10^-6) = 5.546

pH = 14-5.546 = 8.454

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