A) Draw the system and use the mirrorequation to determine thecharacteristics of

Question

A) Draw the system and use the mirrorequation to determine thecharacteristics of theimage.

B) Now you move the object in towardthe vertex of the mirror,ending with the object at a distance of25.0cm from the vertex.

7.Research the mirror andoptical system of theHubble Space Telescope. Construct a scale drawing of the opticalsystem, explain how this design differs from the basic Newtonianreflector system we discussed in class, and make some comparisonbetween the capabilities of this system and the similar reflectorsystems on the earth.

Explanation / Answer

Sign Convention: d is +ve when along the incidentray. Given: f = - 40 cm; Object distance, u = - 160 cm Object size, OO" = 50 cm 1/v + 1/u = 1/f     v = u.f/(u-f) Substitute, u anfd f to get          v = -53.3cm Magnification, m = -v/u = -53.3/160 = - 1/3 = -0.333    m = v/u = II/OO Image size, II' = m.OO' = 50 cm/3 = 16.7 cm Image is inverted, real and smaller in size; in front of themirror Draw a diagram approximately to scale. (b) Use u' = -25 cm; we get   v' = 66.7 cm Image is forced behind the mirror, erect and virtual;magnified.        m' = -v'/u/ =66.7/25 = 2.67 Image size, II'' = 2.67x50 cm = 134 cm As the object is moved nearer the image moves farther from themirror, increasing in size and move towards infinity as theobject approaches the focus at u = 40 cm As the object is moved still closer(u<40 cm), the image isseen magnified and erect behind the mirror. It ia a virtual imagenow. As the O is moved towards the mirror, the image also comescloser to the mirror. Research on Hubble, you may try yourself, consult internet andget some inforation.

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