let\'s assume the half life for the first order decomposition of a certain pesti

Q: let's assume the half life for the first order decomposition of a certain pesti

t1/2=10.2 years k=0.693/t1/2=0.693/10.2= 0.0679 y^-1 we kno that k=(2.303/t)*log(a/a-x) log(a/a-x) = kt/2.303= 0.0679*4/2.303 log(a/a-x) = 0.1179 a/(3.0*10^-8)= antilog(0.1179) a/(3.0*10^-8) =1.3118 a=3.9354*10^-8M )

ID: 951359 • Letter: L

Question

let's assume the half life for the first order decomposition of a certain pesticide is 10.2 years. if the present concentration of a pesticide in a lake is 3.0x10^-8 M, what was the concentration 4.00 years ago? let's assume the half life for the first order decomposition of a certain pesticide is 10.2 years. if the present concentration of a pesticide in a lake is 3.0x10^-8 M, what was the concentration 4.00 years ago? let's assume the half life for the first order decomposition of a certain pesticide is 10.2 years. if the present concentration of a pesticide in a lake is 3.0x10^-8 M, what was the concentration 4.00 years ago?

Explanation / Answer

t1/2=10.2 years

k=0.693/t1/2=0.693/10.2= 0.0679 y^-1

we kno that

k=(2.303/t)*log(a/a-x)

log(a/a-x) = kt/2.303= 0.0679*4/2.303

log(a/a-x) = 0.1179

a/(3.0*10^-8)= antilog(0.1179)

a/(3.0*10^-8) =1.3118

a=3.9354*10^-8M

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let\'s assume the half life for the first order decomposition of a certain pesti

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