For the reaction K_c = 91.8 at a temperature of 361 degreeC. Calculate the value

Question

For the reaction K_c = 91.8 at a temperature of 361 degreeC. Calculate the value of K_p. Express your answer numerically. For the reaction K_p = 3.24times10^-2 at a temperature of 181 degreeC. Calculate the value of K_c. In Part A, you were given the equilibrium pressures, which could be plugged directly into the formula for K. In Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this data to find all three equilibrium concentrations before you can apply the formula for K. The following reaction was performed in a sealed vessel at 731 degreeC :

Explanation / Answer

Kc=Kp/(RT)^n

where,

Part A

deln= 1-5=-4
Kc=Kp/(0.0821*(361+273))^-4  
so,
Kp = 1.25 *10^-5

Part B

deln= 3-3=0
Kc=Kp/(0.0821*(181+273))^0
so,
Kc = Kp= 3.24*10^-2

Part C

H2          +        I2          - >      2HI
3.2-x               2.5-x                      2x

given ,2.5-x   = 0.05
so,x= 2.45

Kc=[HI]^2/[I2][H2]
    =4.9^2 / 0.05*0.75
   =640.27

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.