For the reaction LiOH (s) Li^+ (aq) + OH^- (aq) + OH^-(aq), K_eq = 4.6 times 10^

Question

For the reaction LiOH (s) Li^+ (aq) + OH^- (aq) + OH^-(aq), K_eq = 4.6 times 10^-3, and the equilibrium concentration for hydroxide ion is [OH^-] = 0.042. What is [Li^+] at equilibrium? A) 0.11 M B) 0.42 M C) An answer cannot be determined without [LiOH] value. D) none of the above Consider the reaction 2N_2O(g) O_2(g) + 2N_2(g). Which of the following will cause a shift in equilibrium to the left? A) 1 and 3 only B) 2 and 3 only C) 1 and 2 only D) All of 1, 2, and 3 E) Neither 1, 2, or 3 Oxidation involves which of the following? A) 2 only B) 3 only C) 1 only D) 1 and 3 only E) 2 and 3 only Assign the oxidation state of each atom in potassium chlorate, KCIO_3. A) K = +1, Cl = +1, O = -2 B) K = +1, Cl = -1, O = 0 C) K = -1, Cl = -1, O = +2 D) K = -1, Cl = +1, O = 0 E) = +1, Cl = +5, O = -2 F) 0.0046 M Identify the substance being reduced in the following reaction CH_4 + 2O_2 - CO_2 + 2H_2O. A) CH_4 B) O_2 C) CO_2 D) H_2O E) none of the above How many protons and neutrons are in _16^34 S? A) 16 p and 18 n B) 16 n and 34 p C) 16 n and 18 p D) 16 p and 34 n E) none of the above

Explanation / Answer

LiOH (s) <==> Li+ (aq) + OH- (aq)

Keq = [Li+][OH-]/[LiOH] As LiOH is solid [LiOH ] = 1

4.6*10^-3 = [Li+][).042]

or, [Li+] = 0.109 ~0.11 M (answer)

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