For the reaction A + 2A +3C ? 4D the following data were obtained run [A] [B] [C

Question

For the reaction A + 2A +3C ? 4D   the following data were obtained

run

[A]

[B]

[C]

Rate of formation of D (mol/min)

1

.10

.20

.30

9.0 x 10^-5

2

.30

.50

.30

8.1 x 10^-4

3

.10

.30

.30

9.0 x 10 ^-5

4

.10

.40

.90

2.7 x 10^-4

a.       Write the rate law for the reaction.

b.      Calculate the value of the rate constant

c.       For run 4, calculate the rate of formation of D when exactly half the A present at the start of the reaction has been used up. ( assume the volume of the reaction mixture remains constant). WORK MUST BE SHOWN TO RECEIVE ANY POINTS OR RATING ( Not trying to yell I just couldn't put it in bold)

run

[A]

[B]

[C]

Rate of formation of D (mol/min)

1

.10

.20

.30

9.0 x 10^-5

2

.30

.50

.30

8.1 x 10^-4

3

.10

.30

.30

9.0 x 10 ^-5

4

.10

.40

.90

2.7 x 10^-4

Explanation / Answer

run 3/run 1 = (.30/.20)^b = (9x10^ -5)/(9 x10^ -5) , b = 0,

order with respect to B = 0,

run 4/run1 = (0.9/0.3)^c= ( 2.7 x10^ -4)/(9x10^ -5) = 3^c = 3 , c =1 ,

order wih respect to C = 1,

run 2/run1 = (0.3/0.1)^a = 8..1 x10^ -4/9x10^ -5 , 3^a = 9 , a = 2 ,

order with respect to A = 2 ,

rate = k[A]^2[C] ,

9 x10^ -5 = k(0.1)^2(0.3) , k = 0.03,

a) rate = 0.03[A]^2[C],

b) rate const k = 0.03 ,

c) rate = 0.03(0.1/2)^2(0.9) = 6.75 x10^ -5

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.