In one molecute of calclum chloride, CaCI_2 there are (enter your answer in digi
ID: 942968 • Letter: I
Question
In one molecute of calclum chloride, CaCI_2 there are (enter your answer in digits) atoms of Ca atoms of Ci 2. One molecule of iron (II), Fe(NO _) contains (enter your answer in digits) atoms of De atoms of N atoms of O 3. What is the molar mass of gotassium dichromate, K_2Cr_2O_2? 4. What is the molar mass of calclum, Ca_1NO_2)_3? 5. The motar mass of glucoss is 180 g/mol and that of meter is 18 g/mol. In 1 mole of each substance, your have (more glucces/more water/the same number of) molecules, 8. The molar mass of sucross, C_18H_20O_ is 342 g/mol. Given 198.8 g of sucross, how many moles (of sucross) do you have? 7. The molar mass of sodium hydroxide, NaOH, is 40 g/mol. How many grams of NaOH are required to yield 0.55 mol? 8. What is the percent suffer (% 8) in copper sulfate, CuSo_4 ? The molar mass of CaSO_4 is 159.6 g/mol. 9. How many grams of carbon are in 38.6 g of glucose, C_8H_sgO_a? 10. The snows the simplest ratio of atoms (smallest whole numbers) in a compound.Explanation / Answer
1.
In one molecule of CaCl2, there are 2 atoms of Cl and 1 atom of Ca.
2.
One molecule of Fe(NO3)2 contains
1 atom Fe, 2 atoms N, 6 atoms O
3.
Atomic mass of K = 39, Cr = 52, O = 16
So molar mass of K2Cr2O7 = 2*39 + 2*52 + 16*7 = 78+104+112 = 294 g
4.
Atomic mass of Ca = 40, N = 14, O = 16
So molar mass of Ca(NO3)2 = 40 + 2*14 + 16*6 = 40+28+96 = 164 g
5.
In 1 mole, we have same number of molecules of any compound.
6.
Number of moles = Given mass/Molar mass = 136.8/342 = 0.4
7.
Mass required = Molar mass*moles = 40*0.55 = 22 g
8.
% S present = Mass of S present/ Mass of 1 molecule = 32/159.6*100 = 20.05 %
9.
1 molecule of glucose (180g) contains : 12*6 g C
So, 38.6 g glucose contains : (12*6)/180 * 38.6 = 15.44 g C
10.
Empirical formula
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