For the series of UV-visible absorption spectroscopic data listed below, fill ou

Question

For the series of UV-visible absorption spectroscopic data listed below, fill out all of the unknown values for each sample (A-J) in the table being sure to use the correct number of significant figures. Where needed, use a molar mass of 200 for the analyte. Show an example calculation for each type of calculation you used. Much appreciated!

2 2 -1 -1 AT L mol. cm cm .ppm cm 0.172 4.23 x 103 1.00 44.9 0.0258 1.35 x 104 C0.520 7.95 x 10 1.00 39.6 0.0912 1.76 3.73 x 103 1.71 × 10-3 0.100 1.00 1.50 9 7 83.6 8.07 x 10 0.789 33.6 11.1 1.35 x 103 7.07 × 10-5 5 2 2 5.23 9.78 x 10 5.24 0.179 1.00 7.19 × 10°

Explanation / Answer

There is a lot of data there, so I'm gonna show you an example of calculations. All you have to do is follow the same procedure for each of the values, and you will fill the table:

These are the expressions you may use in this part:

A = Ebc ---> c = A/Eb ----> b = A/Ec

ppm = mg/L

moles = m/MM

ppm = c * MM * 1000 -----> c = ppm / 1000 * MM

a = E / MM * 1000 -----> E = a * MM * 1000

c = mol / V

A = -log T ----> T = 10-A

T = %T / 100

With all of these expressions, you can actually fill the blanks. I'll do some examples of calculations.

Row A:

T = 10-0.172 = 0.67297 ---> %T = 0.67297 * 100 = 67.297 %

a = 4.23x103 / 200 * 1000 = 0.02115 L / cm mg

c = 0.172 / 4.23x103 * 1 = 4.07x10-5 M

ppm = 4.07x10-5 * 200 * 1000 = 8.14 mg/L or ppm.

If you follow the same procedure, and with the equations above, you may fill the rest of the table. I'm gonna do it with row G too:

Row G

T = 10-0.789 = 0.1626 ---> %T = 0.1626 * 100 = 16.26%

c = 33.6 / 200 * 1000 = 1.68x10-4 M

E = 0.789 / 1.50 * 1.68x10-4 = 3.131x103 L / mol cm

a = 3.131x103 / 200 * 1000 = 0.0157 L / mg cm

Hope this helps.

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