For the series circuit shown, initially the capacitor is uncharged. Then the swi

Question

For the series circuit shown, initially the capacitor is uncharged. Then the switch is connected to position 1 and the capacitor starts to charge. After 8 s, the switch is abruptly switched to position 2 and the capacitor starts to discharge. What is the voltage across the capacitor 6 s after the switch is connected to position 2?

2. For the series circuit shown, initially the capacitor is uncharged. Then the switch is connected to position 1 and the capocitor starts to charpe. Aller 8.00 s the pwish is abeuptly switched to position 2 and the capacitor starts to dischange. Whar is the sotage across the capacitor 6.00 s after the switch is cosnected bo position 22

Explanation / Answer

Here ,

for the circuit

Time constant , T = R *C  

T = 85 *10^3 * 120 *10^-6 s

T = 10.2 s

after 8 s

voltage across the capacitor is

V = 40 * (1 - e^(-8/10.2))

V = 21.7 V

Now, after 6 s

Voltage across capacitor = 21.7 * e^(-6/10.2)

Voltage across capacitor = 12.1 V

the voltage across capacitor is 12.1 V

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