Read each statement A-F carefully (see attached image). Then, select all of the

Question

Read each statement A-F carefully (see attached image). Then, select all of the letters below that represent false statements.

The S_N 2 product formed following the addition of methylacetylene to NaNH_2 and MeBr will have an IR absorbance signal show up in Zone 3. Knowing that a typical ^16 O-H stretch appears at ~ 3400 cm^-1 in the IR, the relative change in vibrational frequency will be less for an ^17 O-H stretch than it would be an ^16 O-D stretch. Carbonyl (C=O stretches typically result in strong vibrational frequencies in the ^1H NMR due to the large change in dipole moment associated with this bond. Ring current is a phenomenon associated with a current caused by pie-electrons. When the current induces a magnetic field which reinforces the external magnetic field, the result will be a deshielding effect on the nuclei. tert-Butyl phenyl acetylene when treated with Na degree _(solid), NH_3(liquid) in methanol will produce an alkene where each vinyl proton will be a doublet with an expected coupling constant (J) somewhere between the range of 12-18 Hz. The product formed after the addition of cyclopentanol to PBr_3 should, in theory, produce a ^1H NMR spectrum having 3 peaks.

Explanation / Answer

A) what is zone 3, no clarity in question

B -false

C- true

D-true

E-true

F-true

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