1a. 1-butene is treated with HBr and peroxides. The product is _ because a _

Q: 1a. 1-butene is treated with HBr and peroxides. The product is ___ because a ___

1a. 1-bromobutane/1o b. propagation c. I2/h d. 3/allylic e. H2/Lindlar’s catalyst , convert alkene to alkyl dihalide with Br2, then do elimination reaction.

ID: 927036 • Letter: 1

Question

1a. 1-butene is treated with HBr and peroxides. The product is ___ because a ____ radical intermediate forms.

1-bromobutane/1o

1-bromobutane/2o

2-bromobutane/1o

2-bromobutane/2o

1b. Ethylene is used to make polyethylene. The mechanistic step that makes the chain grow is:

initiation

propagation

termination

1c. Your method to synthesize cyclopentyl iodide from cyclopentane is:

I2/h

NBS/h followed by OEt- followed by HI

Cl2/h followed by OEt- followed by HI

1d. NBS is a brominating agent. 1-butene reacts with NBS to form C4H7Br. The Br is bonded to carbon ____, which is the ___carbon .

1/alpha

2/beta

3/allylic

4/gamma

1e. Propyne is converted to propene by __(a, b, or c)_; but propene is converted to propyne by __(d, e, or f)_.

HBr

H2/Lindlar’s catalyst

H2/Pt

convert alkene to alkyl halide with HBr, then do elimination reaction

convert alkene to alkyl dihalide with Br2, then do elimination reaction

convert alkene to ROH, then use NaOEt

Explanation / Answer

1a. 1-bromobutane/1o

b. propagation

c. I2/h

d. 3/allylic

e. H2/Lindlar’s catalyst , convert alkene to alkyl dihalide with Br2, then do elimination reaction.

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1a. 1a. A simple pendulum of length L and mass M has frequency f.To increase its

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1a. 1-butene is treated with HBr and peroxides. The product is ___ because a ___

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Explanation / Answer

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1a. 1-butene is treated with HBr and peroxides. The product is _ because a _