How many molecules are there in an ideal gas with the volume of 7.71 L at STP? A

Question

How many molecules are there in an ideal gas with the volume of 7.71 L at STP?
An open flask sitting in a lab fridge looks empty but, we know that actually it is filled with a mixture of gases called air. if the flask volume is 1.00 L in the air is at standard temperature and pressure how many gaseous molecules does the flask contain?
What volume would 1.75×10 to the 23rd molecules of an ideal gas occupy at STP? How many molecules are there in an ideal gas with the volume of 7.71 L at STP?
An open flask sitting in a lab fridge looks empty but, we know that actually it is filled with a mixture of gases called air. if the flask volume is 1.00 L in the air is at standard temperature and pressure how many gaseous molecules does the flask contain?
What volume would 1.75×10 to the 23rd molecules of an ideal gas occupy at STP?
An open flask sitting in a lab fridge looks empty but, we know that actually it is filled with a mixture of gases called air. if the flask volume is 1.00 L in the air is at standard temperature and pressure how many gaseous molecules does the flask contain?
What volume would 1.75×10 to the 23rd molecules of an ideal gas occupy at STP?

Explanation / Answer

(1). Volume = 7.71 L

At STP,

22.4 L = 1 mole of gas

7.71 L = 7.71 / 22.4 moles of gas

= 0.344 moles of gas

Now, we know that,

1 mole gas = 6.023x1023 molecules

0.344 moles of gas = 0.344 * 6.023x1023 molecules

= 2.072x1023 molecules of gas.

(2). Volume = 1.00 L

At STP,

22.4 L = 1 mole of gas

1.00 L = 1.0 / 22.4 moles of gas

= 0.044 moles of gas

Now, we know that,

1 mole gas = 6.023x1023 molecules

0.044 moles of gas = 0.044 * 6.023x1023 molecules

= 2.65x1022 molecules of gas.

(3). Number of molecules = 1.75x1023

At STP,

6.023x1023 molecules = 22.4 L volume

1.75x1023 molecules = ( 22.4 / 6.023x1023 ) * 1.75x1023

= 6.51 L volume

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