How many mL of 0.2 M NaOH are needed to neutrilize 50.00 mL of a 0.150 M solutio

Question

How many mL of 0.2 M NaOH are needed to neutrilize 50.00 mL of a 0.150 M solution of HCl? A). 20.0 mL b) 37.5 mL c) 66.7 mL   d) 125.0 mL   e) 160.0 mL

A supersaturated solution   A) Contains as much solvent as it can hold B) will rapidly come out of soution (precipitate) when just a little more solute is added   C) contains no double bonds D) contains dissolved solute in equilibrium with undissolved solid E) will dissolve readily in any solvent

How many grams of NaCH are needed to make 1.0 L of a 2.50% solution a) 0.005 g   b) 6.25 g c) 22.5 g d) 25.0 g c) 250 g

Explanation / Answer

The reaction between NaOH and HCl is NaOH+ HCl---> NaCl + H2O

Moles in 50ml of 0.150 M = 0.150*50/1000=0.0075

From the reaction, moes of NaOH required = 0.0075 (1:1 ratio of NaOH and HCl)

Hence L of NaOH= 0.0075/0.2= 0.0375L =37.5 ml

b) Super saturated solution contains more solid than that can be dissolved. B and C are correct

c) 100 L contains 2.5 gNaOH

1000 L Contains 2.5*1000/100 =25 gms

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