8) Given the following equation, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -

Question

8) Given the following equation, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -2074 kJ

Calculate G°rxn for the following reaction. 21 CO2(g) + 28 H2O(g) 7 C3H8(g) + 35 O2 g)

A) +14518 kJ B) -2074 kJ C) -14518 kJ D) -296 kJ E) +2074 kJ

19) Given the following equation, N2O(g) + NO2(g) 3 NO(g) G°rxn = -23.0 kJ

Calculate G°rxn for the following reaction. 3 NO(g) N2O(g) + NO2(g)

A) -69.0 kJ B) 69.0 kJ C) 23.0 kJ D) -7.67 kJ E) -23.0 kJ

22) Given the following equation, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -2074 kJ

Calculate G°rxn for the following reaction. 7 C3H8(g) + 35 O2(g) 21 CO2(g) + 28 H2O(g)

A) -14518 kJ B) +2074 kJ C) -2074 kJ D) -296 kJ E) +14518 kJ

25) Estimate G°rxn for the following reaction at 417 K.

HCN(g) + 2 H2(g) CH3NH2(g) H°= -158.0 kJ; S°= -219.9 J/K

A) +61.9 kJ B) -66.3 kJ C) + 66.3 kJ D) +250 kJ E) -250 kJ

26) Calculate S°rxn for the following reaction. The S° for each species is shown below the reaction.

N2H4(l) + H2(g) 2 NH3(g)

S° (J/molK) 121.2 130.7 192.8

A) -59.1 J/K B) +118.2 J/K C) -202.3 J/K D) +178.9 J/K E) +133.7 J/K

29) Given the following equation, H2O(g) + CO(g) H2(g) + CO2(g) G°rxn = -28.6 kJ

Calculate G°rxn for the following reaction.

5 H2(g) + 5 CO2(g) 5 H2O(g) + 5 CO(g)

A) +143.0 kJ B) -28.6 kJ C) -143.0 kJ D) +5.72 kJ E) -5.72 kJ

Explanation / Answer

Given the following equation, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -2074 kJ

Calculate G°rxn for the following reaction. 21 CO2(g) + 28 H2O(g) 7 C3H8(g) + 35 O2 g)

A) +14518 kJ B) -2074 kJ C) -14518 kJ D) -296 kJ E) +2074 kJ

3 CO2(g) + 4 H2O(g) --- > C3H8(g) + 5 O2(g)

G°rxn = + 2074 kJ

21 CO2(g) + 28 H2O(g) --- >7 C3H8(g) + 35 O2(g)

G°rxn = + 2074*7= 14518 kJ

Hence the correct answer is A) +14518 kJ

19) Given the following equation, N2O(g) + NO2(g) 3 NO(g) G°rxn = -23.0 kJ

Calculate G°rxn for the following reaction. 3 NO(g) N2O(g) + NO2(g)

A) -69.0 kJ B) 69.0 kJ C) 23.0 kJ D) -7.67 kJ E) -23.0 kJ

3 NO(g) ---- > N2O(g) + NO2(g)

G°rxn = + 23.0 kJ

Hence the correct answer is C) +23.0 kJ

22) Given the following equation, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -2074 kJ

Calculate G°rxn for the following reaction. 7 C3H8(g) + 35 O2(g) 21 CO2(g) + 28 H2O(g)

A) -14518 kJ B) +2074 kJ C) -2074 kJ D) -296 kJ E) +14518 kJ

, C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g) G°rxn = -2074 kJ

7 C3H8(g) + 35 O2(g) 21 CO2(g) + 28 H2O(g)

G°rxn = -2074 kJ *7= - 14518 KJ

25) Estimate G°rxn for the following reaction at 417 K.

HCN(g) + 2 H2(g) CH3NH2(g) H°= -158.0 kJ; S°= -219.9 J/K

A) +61.9 kJ B) -66.3 kJ C) + 66.3 kJ D) +250 kJ E) -250 kJ

G°rxn = H° -T S°

= -158.0 kJ *1000 – 417 K* -219.9 J/K

= - 158000 + 91698.3

= - 66301.7 J

= -66.3 kJ

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