3. Butadiene (C4H)reacts with itself at 250 °C to form a dimer with the formula
ID: 918418 • Letter: 3
Question
3. Butadiene (C4H)reacts with itself at 250 °C to form a dimer with the formula CgH12 The reaction is second order in C4H6 (a) what is the rate law for the reaction If the rate constant is 4.0 x 10. In (a) What is the rate law for the reaction If the rate constant is 4.0x 10 Ms rate constant is 4.0 x 102 M1 1, and (i 1, and (b) if the initial concentration of CaHe is 0.800 M, what is the concentration of C,H, after: 0 10 min, (ii) the first-half-life? 4. Dinitrogen pentoxide, N20s, decomposes as shown below: 2 N205 (3)4NO2(8)+O g) The reaction is first order with a half-life of 400 s. (a) What is the rate constant, k, for reaction (b) If the initial concentration of N20s is 0.400 M, what is the initial rate for the reaction, and (c) how long will it take for the concentration to reach 0. 0500 M? 5. A possible mechanism for a reaction that takes place in solution is Step (): Ce+ Mn2Ce+Mn Step(2) ce + MnCe+ Mn Step (3) Mn Mn2+T slow fast fast (a) What is the overall reaction (b) what is the predicted rate lawExplanation / Answer
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3.a.
- dCC4H6 /2dt = 4.0x10-2 C2C4H6
b. Or in its integral form
1/CC4H6 = 4.0x10-2 t + 1/0.800 (t=600 s)
= 24 + 1.25 = 25.25
CC4H6 = 0.04 M
c. CC4H6 = 0.800/2 = 0.400 M
4.
a. k = 0.693/t1/2 = 0.693/400 = 1.73x10-3 s-1
b. - dc/2dt = kC= 1.73x10-3 s-1 x 0.400 M = 6.92x10-4 mol/s
c.
lnC = -kt + lnCo
ln0.050 = -1.73x10-3 s-1 x t + ln0.400
solve for t
5.
a. 2Ce4+ + Tl+ = 2Ce3+ + Tl3+
b. –dCCe4+/dt = kCCe4+ (consider the slow step)
c. Mn3+ and Mn4+
d. Mn2+
6.
a. K = [NO2]2 / [N2O4] = 0.1342 / 0.90 = 0.02
7.
K = [CO]2 /[CO2]
[CO] = (K[CO2])1/2 = 0.24
8.
a. pV=nRT n/V=C
p= CRT
Kp = pSO32 / (pSO22.pO2) = Kc (RT)-1
b.
Kc = 1/3.5x10-3 = 285
9.
The reaction quotient has the same expression as K, but the concentrations are the actual ones (given here), not the equilibrium ones. Only if Q = K the reaction is at equilibrium.
If Q>K the reaction goes from right to left.
10.
See Le Chatelier principle.
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