an insulated container is used to hold 45.70 g of water at 35.90 c. A sample of

Question

an insulated container is used to hold 45.70 g of water at 35.90 c. A sample of copper weighing 16.40 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.10 c. the heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. given that specific heat of solid copper is 0.385 j /(g*c), calculate the max temp of the water in the insulated container after the copper metal is added

Explanation / Answer

we know that

heat lost by hot body = heat gained by cold body

also

heat = mass x specific heat x temp change

Q = m x s x dT

now

in this case

hot body is copper

and

cold body is water

so

heat lost by copper = heat gained by water

m x s x dT of copper = m x s x dT of water

let the final equilibrium temperature be Tf

so

16.40 x 0.385 x ( 100.1 - Tf) = 45.70 x 4.184 x ( Tf - 35.90)

100.1 - Tf = 30.283 ( Tf - 35.90)

solving

we get

Tf = 37.95

so

the max temp of water will be 37.95

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