Determine the pH of each of the following solutions. Part A 4.5×10 2 M HI Expres

Question

Determine the pH of each of the following solutions.

Part A

4.5×102 M HI

Express your answer to two decimal places.

Part B

9.91×102 M HClO4

Express your answer to three decimal places.

Part C

a solution that is 4.8×102 M in HClO4 and 5.5×102 M in HCl

Express your answer to two decimal places.

Part D

a solution that is 1.11% HCl by mass (Assume a density of 1.01 g/mL for the solution.)

Express your answer to three decimal places.

Determine the pH of each of the following solutions.

Part A

4.5×102 M HI

Express your answer to two decimal places.

pH =

Part B

9.91×102 M HClO4

Express your answer to three decimal places.

pH =

Part C

a solution that is 4.8×102 M in HClO4 and 5.5×102 M in HCl

Express your answer to two decimal places.

pH =

Part D

a solution that is 1.11% HCl by mass (Assume a density of 1.01 g/mL for the solution.)

Express your answer to three decimal places.

pH =

Explanation / Answer

PartA:
M = 4.5*10^-2
[H+] = 4.5*10^-2

Ph = -log[H+]
Ph = -log[4.5*10^-2]
Ph = 1.35
...........................................
PartB:
M = 9.91*10^-2
[H+] = 9.91*10^-2

Ph = -log[H+]
Ph = -log[9.91*10^-2]
ph = 1.004
..................................................
partC:
M = 4.8*10^-2

[H+] = 4.8*10^-2

ph = -log[H+]
Ph = -log[4.8*10^-2]
Ph = 1.32
...................................................
PartD:

a solution that is 1.11% HCl by mass (Assume a density of 1.01 g/mL for the solution.)

density of the solution = 1.01 gm/ml
1ml of solution is having 1.01 gm.
100 ml of the solution is having 101 gm.

mass% = (mass of solute/mass of solution)*100

1.11% of 101 gm
   = 101*1.11/100 = 1.12 gm.

M = (wt/mol.wt)*(1000/vol.in ml)
M = (1.12/36.5)*(1000/100)
M = 0.307
[H+] = 0.307

Ph = -log[H+]
Ph = -log[0.307]
Ph = 0.513

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