The graph below represents the titration of an amino acid with NaOH solution. Vi

Question

The graph below represents the titration of an amino acid with NaOH solution. View the titration and answer the questions below (parts a through e) (a) At what pH are about V2 of the carboxyl groups ionized? 10 Number p = 9.69 2.00 Pl-8.0 6.01 (b) Where does the amino acid have a net charge of +1? O below pH 2.34 O at pH 2.34 O at pH 6.01 O at pH = 9.69 O above pH 9.69 pK: = 2.34 0.5 1.0 2.D OH-(equivalents) (c) At what point has enough base been added to react with ½ of the COOH groups? continued below Number Number e quivale nts OH pH=1 PreviousGive Up & View Solution Check Answer Next Exit

Explanation / Answer

a) 2.34     ( since pH = pka then we have acid form of COOH = base form of COOH i.e COO- pka of COOH is 2.34)

b) below 2.34  

c) 0.5 equivalents OH-

d) 6.01  

e) 6.01

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